Recent content by lkj-17

Both Int {(t-tau)*sin(a*tau)}d(tau) and Int {(tau)*sin(a*(t-tau)}d(tau) will give the same answer (a*t-sin(a*t))/(a^2), where tau = 0..t Anybody can give a hint how to do the integration. Personally, I think neither integration by parts nor substitution are suitable methods.

Unable to obtain (1/2)*t*sin(t) from this method. Would you please show a little steps?

Any simple way to do it? If this happened in the exam, it will be a disaster!

How to integrate sin(t-tau)cos(tau)d(tau) where tau = 0..t Maple gives answer (1/2)*t*sin(t) How can we compute it by hand?

How to use power series to solve this non-linear differential equation?