Recent content by lolcheelol

i don't understand, do u mean 3.22x10^-6/8 = λ

Homework Statement In a Young's double-slit experiment, two rays of monochromatic light emerge from the slits and meet at a point on a distant screen, as in the figure below. The point on the screen where these two rays meet is the eighth-order bright fringe. The difference in the distances...

thanks for all your assistance guys, i really appreciate it.

it would be going to the right(clockwise) because T2>T1

i think counterclockwise because the tension is positive.

T1 = 1.00*1.4+9.80 = 11.2 -T2 = 4.00*1.4-19.6 = -14 (thanks for all your help and patience so far btw.) i may be jumping ahead, but in order to find the direction don't you need x and y?

sorry, math error. i end up with a = 1.4 (-9.80+19.6) = 9.8 --- (-1.00a-4.00a) = -5a 9.8 - 5a = 2.00a 9.8 = 7a 1.4=a

i come up with -(1.00a + 9.80)-(4.00a-19.6)=2.00a -29.4 - 5a = 2.00a -29.4 = 7a -4.2 = a does that look correct? would that be the magnitude of the acceleration?

T1 = (1.00)a + 9.80 -T2 = (4.00)a - 19.6 that better?

T1-(9.8)(1.00)=(1.00)a T1+T2=(2.00)a T2+(4.00)(9.8)(sin(30))=(4.00)a T1-(9.8)=(1.00)a --- T1 = (1.00)a/(9.8) T2+19.6=(4.00)a ---- T2 = (4.00)a/(19.6) Insert T1 and T2 into 2nd equation (1.00)a/(9.8) + (4.00)a/(19.6) = (2.00)a

A:T1-(9.8)(1.00)=(1.00)a B:-T1+T2=(2.00)a C=-T2+(4.00)(9.8)(sin(30))=(4.00)a do these look correct?

kinetic friction? i thought it would have been mgsin∅

they were the x components from all 3 blocks and the y components from the blocks. I'm not sure how to do what you're saying to do, any help?

so you would separate them into Fx and Fy vectors? Fx = -T1+T2 =ma Fy = T1 - W = ma does that look correct?

Homework Statement In the figure below, M1=1.00 kg, M2=2.00 kg and M3=4.00 kg. Theta is 30.0°. The pulley and all surfaces are frictionless. Find the tension in the two strings and the direction (entire system to the left/counterclockwise or entire system to the right/clockwise) and...