Calculating Wavelength in Young's Double-Slit Experiment

AI Thread Summary
In a Young's double-slit experiment, the eighth-order bright fringe occurs where the path difference between two rays of light is 3.22 x 10^-6 m. The relevant equation for calculating the wavelength (λ) is derived from the condition for maxima, which states that the path difference equals nλ. The user is unsure how to determine the angle (θ) needed for the calculation but is guided that the wavelength can be found by dividing the path difference by the order of the fringe (8). The correct approach is to use the formula λ = path difference / m, leading to λ = 3.22 x 10^-6 m / 8. This discussion emphasizes the relationship between path difference, fringe order, and wavelength in the context of the double-slit experiment.
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Homework Statement



In a Young's double-slit experiment, two rays of monochromatic light emerge from the slits and meet at a point on a distant screen, as in the figure below. The point on the screen where these two rays meet is the eighth-order bright fringe. The difference in the distances that the two rays travel is 3.22 10-6 m. What is the wavelength of the monochromatic light?

27-figure-06a.gif


d=3.22x10^-6
m=8
λ=?

Homework Equations



sinθ = mλ/d

The Attempt at a Solution



well i derived the equation
sinθ*d/m = λ

I'm pretty sure I can figure it out once I get the θ, but I have absolutely no idea how to solve for it in this case.

I'm also not sure if you need y=L*tanθ

any help is appreciated
 
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In the double slit experiment Maxima occur when the path difference between the 2 sources = nλ
That should be all you need !
 
i don't understand, do u mean

3.22x10^-6/8 = λ
 

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