Recent content by lolilovepie

  1. L

    Completely expand as a sum/difference of logs

    after continuing would it be: [log 2x^4 + log (x-15)^3] - [log 12 + log (x^4-16)^1/2] and then use the power rule? [4 log 2x + 3 log (x-15)] - [log 12 + 1/2 log (x^4-16)]
  2. L

    Completely expand as a sum/difference of logs

    1) yeah, that's what i meant to say, but i didn't know how to do the exponents 2) ok okay thanks! did I solve the problem right because I'm not very sure :\
  3. L

    Completely expand as a sum/difference of logs

    Homework Statement Completely expand as a sum/difference of logs log [ ( 2x^4(x-15)^3) / (12 sqrt (x^4-16) ] Homework Equations The Attempt at a Solution log 2x^4(x-15)^3 - log 12 sqrt (x^4-16) 3 log 2x^4(x-15) - 1/2log 12 (x^4-16)
  4. L

    Express the length y of the building as a function of the width x

    sorry, it also came with this picture that i forgot to post : http://tinypic.com/r/2d9w9xk/5 yeah , that's all it say
  5. L

    Express the length y of the building as a function of the width x

    The answer in the book was a) y(x)=500/x b) c(x)=300x+(100,000/x) -600 it also came with this image (forgot to post it) : http://tinypic.com/r/2d9w9xk/5
  6. L

    Express the length y of the building as a function of the width x

    This part is my work listed below! not the answer from the book! (sorry for the confusion) : (a) Area=xy, so 500=xy, y=500/x (b) Perimeter=2(x+y), so perimeter=2(x+500/x)=2((x^2+500)/x). The cost C is $100*perimeter, so C=$100*2((x^2+500)/x)=200((x^2+500)/x)
  7. L

    Express the length y of the building as a function of the width x

    Homework Statement A small office unit is to contain 500 feet sq of floor space. (a) Express the length y of the building as a function of the width x. (b) If the walls cost $100 per running foot, express the cost C of the walls as a function of the width x. (Disregard the wall...
Back
Top