Recent content by lolittaFarhat

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    Finding conditions that assure that a holomorphic function i

    ##\frac{dH}{dx}## and ##\frac{dH}{dy}## in V are continuous, how can this help?
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    Finding conditions that assure that a holomorphic function i

    Let H be a real-valued function of two real variables with continuous first partial derivatives. If h(z)=h(x+i y)= u(x,y)+iv(x,y)is holomorphic in a region V, and H(u,v)=0. Find a condition on H under which one can conclude that h is a constant . Of, course H is the zero function can do the job...
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    Geometric Interpretation of complex numbesr

    z1,z2,z3 are distinct complex numbers, prove that they are the vertices of an equilateral triangle if and only if the following relation is satisfied: z1^2+z2^2+z3^2=z1.z2+z2.z3+z3.z1 so i shall show that |z1-z2|=|z1-z3|=|z2-z3|but i do not know how to start.
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    Solve GAXPY Operations for Matrix A & Vector x

    A is an nxn matrix, I is its identity and should be also an nxn matrix, k must be equal to n because we want A-xrI . Here is the exact statement of the problem: Let A ∈Rnxn, x ∈ Rk. Find the first column of M = (A − x1I)(A − x2I)...(A − xkI) using a sequence of GAXPY’s operations.
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    Solve GAXPY Operations for Matrix A & Vector x

    what you thought is absolutely right, A is a matrix in R^(nxn) and x is an element of R^K . r is a real variable that is equal to k. Sorry for misstating the problem statement.
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    Solve GAXPY Operations for Matrix A & Vector x

    Homework Statement Let A be an nxn matrix belonging to R and x be a vector of length k belonging to R. Find the first column of M = (A − x1I)(A − x2I)...(A − xrI) using a sequence of GAXPY’s operations. Homework Equations GAXPY: General matrix A multiplied by a vector X plus a vector Y The...
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    Proving that a subspace of C is a field

    Homework Statement Show that the only m for which the subspace of C given by {z ∈ C: Im(z) = m Re(z)} is a field is m=0. Homework Equations Field axioms The Attempt at a Solution I tried to prove one direction : - If z is in the subspace, Re z>0 and m≠0 then Arg z<Arg z^2, so z^2 is not in...
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