Recent content by loplol

ok lol kinda obvious isn't it ok here's a revised version of 2 (Y \ X) ∪ Z = (Y ∪ Z) \ (X \ Z) let x be in (Y \ X) ∪ Z -x is in Y and Z but not in X, so x is in X\Z -x is in Y and Z but not in X, so (Y ∪ Z) \ X let x be in (Y ∪ Z) \ (X \ Z) -x is in Y and Z, so x is in Y∪Z -x is in Z but...

what do you mean when you say show the other way? is the 'other way' this? -x is in X and Z but not in Y, so x is in Y\Z so overall (Y \ X) ∪ Z = (Y ∪ Z) \ (X \ Z) let x be in (Y \ X) ∪ Z -x is in Y and Z but not in X, so x is in X\Z -x is in X and Z but not in Y, so x is in Y\Z also (Y ∪...

ok i understand 1) heres my attempt at 2) (Y \ X) ∪ Z = (Y ∪ Z) \ (X \ Z) let x be in (Y \ X) ∪ Z -x is in Y and Z but not in X, so x is in X\Z also (Y ∪ Z) \ X, because x is in Y and Z but not in X hence (Y \ X) ∪ Z = (Y ∪ Z) \ (X \ Z) THIS OK?

Homework Statement Prove where X and Y are both sets use theoretic reasoning i) Z \ (X \cap Y) = (Z \ X) \cup (Z \ Y) ii)(Y \ X) \cup Z = (Y \cup Z) \ (X \ Z) iii) Z \ (Y \ X) = (X \capZ) \cup(Z \ Y) Homework Equations \ = set difference The Attempt at a Solution i know you don't do other...