To fully graph it, you would need a 4-dimensional graph, with axes x,y,a,b, so that x+y\imath=\frac{1}{a+b\imath}.
You could have 2 3-D graphs, z=\Re\left({\frac{1}{x+y\imath}}\right) and z=\Im\left({\frac{1}{x+y\imath}}\right).
This reminds me of the debate of Pluto's...planethood.
The only reasons you would see a black object are
1) it's not truly black and reflects some light,
2) you "see" it because it is different from its surroundings.
If you were in a sealed room, painted totally black, and you shined a...
You could get someone to stand next to you and clap when they see the wooden blocks hit, with you looking away. Then, you can measure the time between the 2 claps.
Hint: Draw a picture and use the formula for period of a pendulum. Once you find the height between the highest and lowest points, you can find the kinetic energy.
You could reach a compromise of
k
k+1
k+1/k
k+1/(k+1)
k+1/(k+1/k)
k+1/(k+1/(k+1))
...
In this way, the values for k=-1 become:
-1,0,-2,[\tex]und,-1.5,\to-1,-1.\overbar{6},\to-2,-1.6,\to-1.5,-1.625,\to-1.\overbar{6},..., tending towards -\frac{1+\sqrt5}{2}
And for k=0...
The amount of matter being converted to energy is not proportional to the mass, it is constant. For example, for m=1000 and r=1, it will take 1000 seconds.
1) v=\frac{\sqrt{2rmt-r^2t^2}}{m}c
2) a=\frac{rm-r^2t}{m\sqrt{2rmt-r^2t^2}}c
3a) \displaystyle\int^{t}_{0}...
A spaceship of mass m\ \text{kg} is propelled by converting r\ \text{kg} of its mass into energy every second. Assume no friction and a perfectly efficient system.
1) Find the velocity of the spaceship at time t.
2) Find its acceleration at time t.
3a) Find the distance it has traveled...
We had a similar problem in our physics class, but my physics teacher says the solution is incorrect.
1) How long was the impact, if it traveled .2 cm at 20 m/s? (This is the part that is incorrect.)
2) Ft=m(v_2-v_1)