Well, I found the torque of these two forces:
τP=rxF or τ=r*Fsinθ, where r=0.71, F=50N, and θ=135°
τP=25.1Nm so τtotal=50.2Nm clockwise
However, this is where I get lost. Isn't the angle of F4 and the lever arm 0? And if it isn't, the equation has two variables, the distance and the angle. Is...