ok.. well this is what i did:
3^3x-2/2^6x-4 * 3^x-1/2^2x-2 = 3^2/2^4
3^4x-3/2^8x-6=3^2/2^4
Therefore, 4x-3/8x-3 = 1/2
*cross-multiply* 8x-6 = 8x-6
0=0
?
Well for no. 1 this is what I've tried but i keep getting the wrong answer:
*2nd step* 3^3x-2/ (2^2)^3x-2 * (2^2)^1-x/3^1-x = 9/16
3^3x-2/2^6x-4 * 2^2-2x^3^1-x = 9/16
2^-8x+6/3^-4x+3 = 3^2/2^4
Therefore, -8x+6/-4x+3 = 1/2...
i'm having problems with two questions. Please help me! Thanks! I've tried everything but i can't solve them... :confused: :frown:
1) Solve: (3/4)^3x-2 * (4/3)^1-x = 9/16
2) Solve for x : 3(3^x) + 9(3^-x)=28
A copper vessel of mass 0.1 kg contains 0.2 kg
of water at 25°C. A lump of copper which had
stayed in a furnace for some time is transferred
quickly from the furnace into the water. The
temperature of water rises to 45°C finally. The
massof the copper lump is 0.1 kg and its specific...
I can't seem to find the answer.. can anyone help me please?
0.5kg of water at 80°C is poured into a copper
vesselat 10°e. The final temperature of the water
inthecopper vessel is 70°C and the specific heat
capacityof copper is 400 J kg-1°C-I.
(a) Findthe energy loss of the water...