Recent content by M.E. Tom

Vidar, Could you go into a little more detail? Also, torque is in Nm not N/m so I'm confused by your example. You used the motor torque of 1450Nm divided by the moment arms (0.0375m, 0.0889m) to calculate the resulant force for each So basically (1450Nm/0.0375m)/0.0375m=1031111N/m...

No, I understand that power is constant through the belted drive, the torque and speed change to keep this constant. Bandit127, you hit on my though exactly with your example Because, I keep thinking about it in that way. As a 3.5in(88.9mm) lever driving the belt, therefore I want...

I had completely forgotten about Torque copules. From Wikipedia: A Couple is a system of forces with a resultant (a.k.a. net, or sum) moment but no resultant force. Another term for a couple is a pure moment. Its effect is to create rotation without translation, or more generally without any...

I think I'm over thinking this, so someone set me straight. If I have an eletric motor with a 75mm OD shaft making 1450Nm of torque, and I add a 7in pulley/sheave to the motor shaft. Would the torque change? Half of me says yes other half of my brain thinks no. Torque = Force *...

Ok, this makes perfect sense. I drew the FBD not thinking about it moving and then confused myself when summing forces. When it is moving then "P" will have to provide both the Torque and the Acceleration force. How would you draw that resultant force?

Hello, I have been trying to set up a free body diagram for a power screw in a horizontal application. Every example I find they are using a power screw to lift or lower a load not move it left to right. I have attached the example from the textbook, along with my work so far...