Recent content by MadPhysics08

now...i understand! i have to reinstall all the drivers again after my pc reformated the directx, realtech, ect...thank u so this thread is close...

my brother installed a new video card and a new RAM... i have three hard drives... drive c, drive d and drive e i am aware about the outcome after i reformat my pc and i freshly knew in how to reformat a pc and i haven't try it in actual... i learned only on youtube my drive e is empty...

opps... sorry i was wrong for multiplying of 300kg(10m/s)=3000kg*m/s not 30000kg*m/s and multiplying 300kg*m/s(4.0m/s)=1200kg*m/s not 4800kg*m/s V2=8.82m/s

to the find final velocity of empty cart... in the equation...let P the momentum P(initial)=P(final) MV1+ MV2 = MV1 + MV2 300kg(10m/s)+0=300kg(4.0m/s)+100kgV2 3000kg*m/s-4800kg*m/s=100kgV2 20400kg*m/s=100kgV2 ----------------------(divided by 100kg) 100kg V2=204m/s(final velocity of the empty cart)

work done by gravitational force(W=-mgcos(θ+90)) is negative because it opposed the direction of W=F*dcosθ

okay... There three forces acted on the sphere: tension(T), applied force F and gravitational force(mg) so.. W=T*Scosθ=0 the displacement of the sphere along the arc length is perpendicular to the tension While.. W=-mg*d cos(θ+90)=-mg*dsinθ (trigonometric identity of cos(θ+90)=sinθ) because...

thnks tim... Can i asked one favor... please... i need a hint for the problem number 2...

so, let d be the displacement W(work)=F*dcosθ ∑F=ma=0 then, ∑F=W+T+F W+T+F=0 -W*dcosθ + T*dcosθ + F*dcos(θ+90) [T*dcosθ=0 because they are perpendicular] W*dcosθ=F*dcos(θ+90) but cos(θ+90)=sinθ w*dcosθ=F*dsinθ F=Wtanθ F=mgtanθ is my solution correct?

Prove that F=mgtanθ Can everyone help me to solve this problem... A small sphere of mass hangs from a string of L as in below. A variable horizontal force F is applied to the sphere in such a way that it moves slowly from the vertical position until the string makes angle θ with the...

Prove that F=mgtanθ Can everyone help me to solve this problem... A small sphere of mass hangs from a string of L as in below. A variable horizontal force F is applied to the sphere in such a way that it moves slowly from the vertical position until the string makes angle θ with the...

hey... i could help u! you can used the ratio proportion method... where: d1=distance1 d2=distance2 t1=time consumed (1st) t2=time consumed (2nd) d1:t1 = d2:t2

so, your initial velocity could be at 2m/s and the final velocity is... then... what do you think.. could be reading the graph is similar with reading the coordinates for (1,2)

hey... remember acceleration is equal to the changed of velocity with respect to time

please... i need a help in integrating the partial fractions i can't proceed to the integration part if i don't understand the patter in finding the constant... that is... if the given is: ʃ ( (x^5+1) / ((x^3)(x+1)) )dx then; ʃ ( x-2 + ( 4x^3+1 ) / ( x^4 + 2x^3) ) ʃ ( x-2 + (...

great...