Recent content by mailmas

Yeah it would orbit if that is the case. And I used the center of mass as the reference point so my final potential energy would be mMG/Radius Earth?

Okay. So the KE_initial would look like: KE = 1/2* m* v_tangental^2 v_tangental = sqrt(G*M/r) KE = 1/2*m*G*M/r

Got it. PE = -(mMG)/r PE_initial + KE_initial = PE_final + KE_final PE_initial = KE_final KE = -(mMG)/r r = Radius Earth + 10,000km = 6.37 * 10^6m + 10,000,000m KE = -((8451kg * (5.98 * 10^24) kg * (6.67 * 10^(-11)) m^3/s^2*kg ) / ((6.37 * 10^6) + 10,000,000)m

Homework Statement Project Thor is a proposed (and terrifying) weapon system where a cylindrical tungsten rod (19600 kg m3 ) about the size of a telephone pole (6.10 m long and 0.300 m in diameter) is dropped from Earth orbit. Imagine you dropped one of these from an orbit 10,000 km above the...

19400 Pa

80000 - (1030)(9.81)(6) = 80000 - 60625.8 = 19374.2

Homework Statement A pipe has a square cross section and a width of 2.00 m and is used to transport salt water from the ocean into a desalination plant. If a pump pushing the water into the pipe at a depth of 1.00 m below the surface of the ocean does so with a pressure of 80 kP a, and the...

FBuoyancy = density*volume*g (1030)(4/3)(pi)(.6)^3(9.81) Then Fnety = 0 = FBuoyancy - Tension - mg Could I solve for tension this way?

Thanks. Do you see anything else wrong with the answer?

Yeah but honestly don't really understand it. So the force I found is the force which acts upwards to an object that is being submerged? Then I should look at the weight force and the difference between those forces must be the force due to tension?

Oh okay yeah I get it. (6.06)(2.59)(2) = 31.39 (6.06)(2.43)(2) = 29.45 (2.43)(2.59)(2) = 12.59 Atot = 73.42 V = 1.46 Wsteel = (8050)(1.46)(9.81) = 116000N

4 Long Parts and 2 for Top and Bottom. I forgot to multiple by 2 for the 6.3. 2(6.3)+62.79 = 75.3 V= 75.3(.02) = 1.5m^3 Wsteel = (8050)(1.5)(9.81) = 119000N

Just calculated it for the other side and got 405. Thanks for the help.

So weight of steel is: Wsteel = (8050)(1.38)(9.81) = 109000N

I think I understand my mistake now. But I don't know which measurement is the width or length so I just chose one to calculate: Area of Long Part = (6.06)(2.59) = 15.69m^2 4*15.69 = 62.79 Area of Top/Bot = (2.59)(2.43) = 6.3m^2 6.3+62.79 = 69 V= 69(.02) = 1.38m^3