Recent content by mak66

It doesn't give any forces in the x direction, just what I typed. So if it was in motion but came to rest I still use the coefficient of kinetic friction? I was using the coefficient of static friction. What I did was find the normal force and multiply by u static friction.

So if F=ma, and I know the acceleration could I solve for the mass? But I feel like that would just be circular. Perhaps I would solve for the force by using F=m(g-a)? So the force is 31.572=m(9.8+2.556), so m=2.555kg. Am I thinking in the right direction?

Sorry about that, it wants to know what the friction is when the coin comes to rest. I know the direction of the friction is up the incline, but other than that I'm stuck.

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