micromass... because f can actually be equal to d. Try this 3^2 + 4^2 = 5^2, and a = b -1 = 4 -1 =3, while c = b + 1 = 4 +1 = 5, which means tha f = d =1.
Another thing... try the formulas. If they work, I'm doing correct math. If they don't, I'm all yours to lapidate. But don't get stuck in minucia. I'm no Newton, but if he had followed the suggestions and objections of Bishop Berkeley, we've probably have no Calculus today, if in addition, no...
I had this before:
b = (a^2 - d^2) / 2d is an equality. Once I changed it to b = (b^2 - d^2) /2d I turned it into an inequality means that b ≠ (b^2 - d^2) /2d, even though the quadratic equation
b^2 - 2db - d^2 = 0 has a solution that is irrational... and here I'm talking about rational...
DonAntonio... you took too many words to reply to this. And yes, I proved the Theorem... as simple as that. Just follow the arguments and don't get excited about nothing. This is not religion or politics. Exactly where is my arguments wrong?
I've got the attached paper... It's interesting, because it deal with an old complex problem is a seemingly simple form, and just using high school algebra. Check it out!
Here is the attackment: