You're very correct in your declarative statement -- I was a fool in not noticing that the value is negative because it is bellow y=0. I now, shall have to re-think my entire enquiry.
Thankyou, mes amis.
The issue is now resolved.
Ah bon!
But my problem still stands, in that the result is that of a negative value -- should I just ignore the negative sign, and conclude that I must calculate the absolute value of integrals like this in future?
EDIT: To treat the integral maybe, as so:
|(\int^{0}_{-10}x^3+2dx)|
Calculus Integration from -10 to 0 Yields a Strange Result [RESOLVED]
As part of a far greater enquiry, I found myself integrating:
\int^{0}_{-10}x^3+2dx
So, I began integrating the x^3+2 component, yielding the result of:
[\frac{x^4}{4}+2x]^{0}_{-10}
Which can then be set out as a...