Recent content by MARK 42

Our teachers modified the question giving us the velocity as 5√3 m/s. Would that work?

What if we consider initial velocity = 0? Assuming the calculation starts from the point the bullets were at rest?

Exactly. I feel the same. I think the question somehow lacks specifications with respect to both velocity and time. Anyways, thanks for your help.

Oh, sorry. If we consider time as 'T' then by traditionally solving, I got Ta = 1/2Tb. I don't know what to do further. The final answer is 1 second. And the displacements, I got Sy for A=Sy for B.

One bullet was fired from Gun A and Gun B each at varying time interval. Both the guns are 10 meters above the ground. Calculate: a) Which gun was fired first. b) Displacement and time at which the two bullets will collide.

Oh, got it. Sorry, silly mistakes. Thanks you were really helpful.

Then how come they changed ma2 to ma1 in the fourth last step? That way, the step should be written as Mg-7mg = Ma1 + 7ma2 right?

Even if equation (ii) multiplied by 7, the equation must be something like this: 7T - 7mg = 7ma2 So, on adding the two equations, 7T and -7T will get canceled out and the result will be Mg-7mg = Ma1 + 7ma1 ...(the acceleration is equal. therefore a1 = a2 .) I don't understand where the 49ma1...

I don't understand the purpose of '1+7x2' either...

In the arrangement shown in the figure, find the acceleration of M in upward direction. The pulleys are light. The strings are mass less and friction between the string and the pulleys is negligible. The options are given. The final answer is (B) and this was the solution: I don't...