Recent content by marstery

Oooh, i get the voltage now--so Vc=Vr=9v. When you say that the capacitor discharges through the 1k resistor doesn't that oppose what M..XY was saying about the capacitor being directional? The steady state voltage of R2 should be 3v. So when the switch is thrown the cap discharges...

Michael, i said series when i really meant parallel. minor details, right? I'm a little confused about the direction that the capactor charges and discharges. does that happen in the same direction, or opposite directions?

The initial conditions are that the switch has been in position 1 for a long time and I am supposed to find Vc(0) and V0(0-). Since it has been a long time the capacitor i assumed that it acts as an open circuit so the current through the capacitor is 0ma and the current around the outer...

Find the voltage drop across the capacitor In a circuit where a voltage source is connected to a capacitor and resistor in series and then connected to another resistor, shouldn't the current going through the capacitor be 0ma after 5 time constants, resulting in a Vc being 0?

here's the diagram...and I am not sure why latex didnt work...and i just realized i titled the thread AC, but its DC. sorry 'bout that

The problem is in bold and my logic/answers/questions are below. Please check my logic and any help with my uncertainties would be...well, helpful. thx The switch has been in position 1 for a long time. Determine the voltage drop Vc(0) and V0(0-). Since it has been a long time the capacitor...

right.

I have an example where a 5v dc source is connected to a 10mh inductor then to 1k and 2k resistors in parallel. In finding the current through the inductor at t=0: written is: IL(0) = 5v / (2/3k) = 7.5 ma what i got was: IL(0) = 5v / (3/2k) = 3.3 ma I'm just checking to make...

oh i see. i had set up a matrix as below where brackets above one another are actually one, but i just can't type them that way here. [1.7ma] = [ (1/5k + 1/20k), -1/20k ] [ Va ] [-2ma ] = [ -1/20k, (1/4k + 1/20k) ] [ Vb ] thanks you for your help!

**I set up my equations based on another example from class, what is the correct matrix set up for an example like this? ..-------Va----R2--I>---Vb------ |...|.....|...| ^...R1......R3...V Is1...|.....|...Is2 .| _____|_____________|______| **so after switching Va and Vb and...

I've got two equations that i want to put into a matrix and solve for Va and Vb: 1.7ma = (1/5k + 1/20k) -1/20k Va -2ma = -1/20k (1/4k + 1/20k) Vb The answers I got were Va= 5.655v and Vb= -5.724 then, using I= (Vb-Va)/R ----> (-11.379/20k) = 0.65ma...