Checking Current in RL Circuit at t=0 - Typo Found?

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The discussion centers on calculating the current through an inductor in an RL circuit at time t=0, where a 5V DC source is connected to a 10mH inductor and parallel resistors of 1k and 2k ohms. The original calculation states that IL(0) equals 7.5 mA, derived from using a parallel resistance of 2/3k. However, the correct calculation shows IL(0) should be 3.3 mA, using a resistance of 3/2k. The confusion arises from a potential typo in the original formula regarding the parallel resistor calculation. The thread seeks clarification on this discrepancy.
marstery
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I have an example where a 5v dc source is connected to a 10mh inductor then to 1k and 2k resistors in parallel.

In finding the current through the inductor at t=0:

written is:
IL(0) = 5v / (2/3k) = 7.5 ma

what i got was:
IL(0) = 5v / (3/2k) = 3.3 ma

I'm just checking to make sure i haven't lost mind or missed something.
 
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The parallel combination of a 1k and 2k resistor is 1/(1+0.5) = 2/3. I think you just forgot the extra 1/ part?
 
right.
 

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