Not really sure how to answer the load attached question, this is all I know about the problem. I believe there is load.
I forgot to mention that it is also possible that some state are impossible.
For state 1, that would mean Vo = R*I
For state 2, I would say current would go to Vo, as D1...
Each state is independent from each other, its like 4 different problems.
In state 1, both are off so its like there is no diode at all and the second resistor is out as well.
which means Vo = Vi
for state 2, I honestly have no idea how to do it. It confuse me a lot. Can you give me some tips...
Homework Statement
I have to find Vo in every diode state possible.
We know diode Vf = 0.7
Homework Equations
Va-Vc < 0.7 = diode OFF
Va-VC > 0.7 = diode ON
The Attempt at a Solution
State 1:
if D1 OFF and D2 OFF
Vo will be equal to Vi
State 2:
if D1 OFF and D2 ON
Vo will be equal to...
Homework Statement
[/B]
A company produces batches of 1800 axle shafts . These are tested to determine the proportion of those with too rough surface according to the standards set in the industry.
A) The quality control department of a sample of 150 axle shafts in a lot and concluded that...
I did that:
p=(15%+25%)/2 =0.2
s= √p(1−p) = √0.2(1−0.2) = 0.4
t=(ME)/((s/sqrt(n))* (sqrt(1-(n/N)))
t = 0.05/((0.4/sqrt(150))* (sqrt(1-(150/1800)))
(1-sigma)=tcdf(-t,+t,n-1)
(1-sigma) = 1
It does not work :(
anyone please help me.
Homework Statement
[/B]
A company produces batches of 1800 axle shafts . These are tested to determine the proportion of those with too rough surface according to the standards set in the industry.
The quality control department of a sample of 150 axle shafts in a lot and concluded that there...
Because the probability is always 0.5 and in Binomial the probability does not change every trials, stays the same.
P is constant in Binomial while in Hypergeomtric its not constant.
I do not really appreciate the fact that I proposed I would use binomial with n p q and being told this is not how we do this problem.
and also I've said multiple times n=8 and you have told me this is incorrect and made me feel like a retard because at the end now you are saying its a binomial...
This is the answer:
Variance = p*n*q
= 8*0.5*0.5
=2
I Cant believe it was that sample and I took 3 days...
I complicated my life for nothing trying to do some complex prob with multiple formulas.