Electronic Circuit with 2 diodes

AI Thread Summary
The discussion focuses on analyzing the output voltage (Vo) in a circuit with two diodes under various states. In State 1, both diodes are off, resulting in Vo equal to the input voltage (Vi). In State 2, with D1 off and D2 on, Vo remains equal to Vi, while in State 3, with D1 on and D2 off, Vo is limited to 0.7V due to the forward voltage drop of the diode. State 4 is deemed impossible because D2 cannot activate without sufficient voltage. The conversation emphasizes the importance of considering load conditions and clarifies that each state should be treated independently.
masterchiefo
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Homework Statement


dNAX4as.png


I have to find Vo in every diode state possible.
We know diode Vf = 0.7

Homework Equations


Va-Vc < 0.7 = diode OFF
Va-VC > 0.7 = diode ON

The Attempt at a Solution


State 1:
if D1 OFF and D2 OFF
Vo will be equal to Vi

State 2:
if D1 OFF and D2 ON
Vo will be equal to Vi

State 3:
if D1 ON and D2 OFF
Vo will be equal to 0.7 since the diode is limiting component it at 0.7

State 4:
if D1 ON and D2 ON
Vo= impossible since D2 will not receive enough volt to activate, it will receive less than 0.7 as the resistance will take some.
 
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masterchiefo said:

Homework Statement


View attachment 204809

I have to find Vo in every diode state possible.
We know diode Vf = 0.7

Homework Equations


Va-Vc < 0.7 = diode OFF
Va-VC > 0.7 = diode ON

The Attempt at a Solution


State 1:
if D1 OFF and D2 OFF
Vo will be equal to Vi

State 2:
if D1 OFF and D2 ON
Vo will be equal to Vi

State 3:
if D1 ON and D2 OFF
Vo will be equal to 0.7 since the diode is limiting component it at 0.7

State 4:
if D1 ON and D2 ON
Vo= impossible since D2 will not receive enough volt to activate, it will receive less than 0.7 as the resistance will take some.
What is your question?

To what extent are the diodes to be considered to be ideal ?
 
masterchiefo said:
if D1 OFF and D2 OFF
Vo will be equal to Vi
Only if there is no load (see state 3).
masterchiefo said:
if D1 OFF and D2 ON
Vo will be equal to Vi
Why?
masterchiefo said:
if D1 ON and D2 OFF
Vo will be equal to 0.7 since the diode is limiting component it at 0.7
I don't understand that argument, and the conclusion is wrong. This state is only possible if there is a load at V0.
masterchiefo said:
if D1 ON and D2 ON
Vo= impossible since D2 will not receive enough volt to activate, it will receive less than 0.7 as the resistance will take some.
I don't understand that argument and the conclusion is wrong.
 
mfb said:
Only if there is no load (see state 3).
Why?I don't understand that argument, and the conclusion is wrong. This state is only possible if there is a load at V0.I don't understand that argument and the conclusion is wrong.

Each state is independent from each other, its like 4 different problems.
In state 1, both are off so its like there is no diode at all and the second resistor is out as well.
which means Vo = Vi

for state 2, I honestly have no idea how to do it. It confuse me a lot. Can you give me some tips ?

For state 3, I came up with a different solution : Vo = Vi - 0.7

For state 4, I came up with the same solution as state 3, Vi -0.7 = Vo
 
SammyS said:
What is your question?

To what extent are the diodes to be considered to be ideal ?
They are perfectly ideal, with vf = 0.7
question is to find Vo in every state as stated in the first post.

Each state is an independent problem.
 
masterchiefo said:
In state 1, both are off so its like there is no diode at all and the second resistor is out as well.
Only if there is no load at V0. But if there is no load, you never have current through D1!
masterchiefo said:
for state 2, I honestly have no idea how to do it. It confuse me a lot. Can you give me some tips ?
If diode 2 is conducting current, where does the current go? What does that mean for the voltages? There are two things you can say.
masterchiefo said:
For state 3, I came up with a different solution : Vo = Vi - 0.7
Only with a load. Otherwise: Where does the current go?
masterchiefo said:
For state 4, I came up with the same solution as state 3, Vi -0.7 = Vo
Again, that needs a load, and the way you answer state 1 there is no load.
You can make an additional statement in this case, based on the conducting diode 2.Can you have a load attached yes or no?
 
mfb said:
Only if there is no load at V0. But if there is no load, you never have current through D1!If diode 2 is conducting current, where does the current go? What does that mean for the voltages? There are two things you can say.
Only with a load. Otherwise: Where does the current go?
Again, that needs a load, and the way you answer state 1 there is no load.
You can make an additional statement in this case, based on the conducting diode 2.Can you have a load attached yes or no?
Not really sure how to answer the load attached question, this is all I know about the problem. I believe there is load.
I forgot to mention that it is also possible that some state are impossible.

For state 1, that would mean Vo = R*I

For state 2, I would say current would go to Vo, as D1 can't receive current in that direction. only from Anode to cathode.
so Vo would be -0.7 - R*I = Vo

I want to clear state 1 and 2 before trying again with 3 and 4, one step at a time so I understand the problem correctly
 
Okay, with possible loads then.
masterchiefo said:
For state 1, that would mean Vo = R*I
That is the voltage drop at the resistor, the difference between two potentials - it is not Vi or V0
masterchiefo said:
For state 2, I would say current would go to Vo, as D1 can't receive current in that direction.
But the resistor can.
masterchiefo said:
so Vo would be -0.7 - R*I = Vo
Right, assuming I is the current flowing through the lower part.
 
masterchiefo said:
.
Staes 1, 3, 4 OK
State 2 wrong.
 

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