okay yes I see where I went wrong...that was silly! But how did you get the numerator to equal
six(x)(1 - cos^2(x)
I got the numerator as sin(x) - ((sin(x))(sin(x)-1))
this would then simplify to
2sin(x) +sin^2(x) (still all over cos(x)) but this isn't right?
I'm sorry, I am actually...
Alright :) I have kind of a few different things I've been working on and I'm not sure which is right or if any of them are...
I considered using the pythagorean identity to get
-Msin^2(x) + Ncos(x) - 2 = 0
and that is my best guess but that doesn't really make sense cause then I am bringing...
alright then...
but would the 2sin(x)'s just cancel out to leave me with
cos^2(x)
2cos(x)
and this would just turn into
cos(x)
2
but that can't be right because I have to get it to be tan(x)sin^2(x) ?
*and the LaTex thing wasn't working for me sorry
Homework Statement
If cos(x) = -¾ or cos = ½ then the value of M and N in the equation Mcos^2(x) + Ncos(x) – 3 = 0 are what?
Homework Equations
Identities I can use:
csc(x) = 1/sin(x)
cot(x) = 1/tan(x)
sec(x) = 1/cos(x)
tan(x) = sin(x)/cos(x)
cot(x) = cos(x)/sin(x)
sin^2(x)...
Yes your right... sorry that should be
tan(x) - (1/2)sin(2x) = tan(x)sin^2(x)
and as for identities i know I have a formula sheet with quite a few.
such as:
csc(x) = 1/sin(x)
cot(x) = 1/tan(x)
sec(x) = 1/cos(x)
tan(x) = sin(x)/cos(x)
cot(x) = cos(x)/sin(x)
sin^2(x) +cos^2(x) = 1
1 +tan^2(x)...
Homework Statement
I need help with trigonometry proofs. the question asks me to prove the following and show all my steps.
Prove that: Tan(x) – ½sin(2x) = tan(x)sin2(x)Homework Equations
I don't know :(
The Attempt at a Solution
No attempt as I don't get it.Any help at all would be...