Recent content by mathstudent79

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    Proving row equivalence is an equivalence relation

    vela, thank you VERY MUCH. I will re-write it,making the adjustment that you suggest. thanks again! have a great day.
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    Proving row equivalence is an equivalence relation

    Homework Statement 'Show that row equivalence is an equivalence relation'. Homework Equations The definition for 'row equivalence' given in the text is, 'two augmented matrices corresponding to linear systems that actually have solutions, are said to be (row) equivalent if they have the...
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    Confusion about continuity question.

    SammyS Thanks so much for your quick response. So, just to be sure, once the discontinuity is removed, the function is continuous everywhere, is that right? Thanks again.
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    Confusion about continuity question.

    1.The Question The function f(x)= x2/x if (x≠0) 0 if(x=0) The Attempt at a SolutionI thought this had a removable...
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    Proving f is a ring isomorphism from R² to C

    Sethric, thank you. As you know, the onto was the part I was especially not sure of. The book I am studying from has very informal and (to my amateur eye) intuitive proofs for onto functions. Along the lines of 'take any b in B. then f(a)=b for some a in A. Thus the function is onto.' Can...
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    Proving f is a ring isomorphism from R² to C

    As for S, I forgot to put: 'We consider the set S of all formal expressions of the form: a+bi, where a,b\inR" Again, with the R, direct quote. Thanks.
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    Proving f is a ring isomorphism from R² to C

    I'm sorry, yes, C is set of Complex Nos. No argument with your observation, but I copied that directly from the book (Modern Algebra, a Natural Approach, Gardiner) Thanks a lot.
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    Proving f is a ring isomorphism from R² to C

    Homework Statement Hi. First post here. I searched for this problem and nothing I saw helped. Sorry. Thanks in advance for help. define a function f: C -----> S by: f(a,b) = a+bi where a,b \inR We leave it to reader to check that f is one-one and onto and that: f((a,b)+(c,d)) =...