Some what, an op-amp circuit. The positive and negative feed the power for the op amp while the common ground, is used to ground the rest of the components that may be used, such as a function generator or oscilloscope, now is it necessary to use common ground for everything else? Or can we just...
Lol let me explain that differently, all of the power suPplies I've seen have a positive and a negative, and some also have standalone ground connection or common ground, so what is it exactly? I know what ground is but what is a "common" ground for?
Okay so I've seen that some not all power supplies have a positive and negative side for the voltag output and in addition have a common ground connection, exactly what is that used for?
Oh okay I see, that makes perfect sense actually. Now if I needed to use a 5 volt low potential connection would the common ground be good enough? Cuz I'm used to the traditional low potential and high potential connections.
Actually you can short the ps_on pin and a common ground pin to turn it on and yes it works I tried millions of times before. And thank you all for your help, but does anyone know why there are so many common ground leads on computer power suPplies? Lol. But thank you all for your helP.
Okay so theoretically let's just say I wanted to use a 5 volt line from a power supply from a computer, would I be able to just connect the + and ground to a bread board to use with an op amp or 555 chip? I hope I explained the question clearly. And thank you, it was really helpful.
okay so I am just slightly confused about current and about how it is drawn from a power supply, so say we have a device that requires 5 volts and uses a max of 550 milliamps, and now let's say that the power supply used is rated at 5 volts, but 32 amps, does this mean that the power supply...
funny u say that, my professor doesn't want us to use the kcl and kvl laws, basically no nodal or mesh analysis, which is why I am stuck, otherwise i can use those laws and figure it out in minutes.
Homework Statement
we need to find V in this circuit. -see attachment
Homework Equations
how do I begin to simplify the circuit?
The Attempt at a Solution