Recent content by mattbeatlefreak

That's what I get:thumbup:

This is not the value I am finding for the final angular momentum. Make sure to use mbvr=(I+mbr2)ωf and to use I as the moment of inertia of the rod, which you previously said, was (1/12)mrL2. Also make sure to use all lengths in meters and masses in kilograms so you get the correct final units...

The angular momentum of an object is Iω. I is the moment of inertia. The moment of inertia of a point mass is mr2.

You are correct in saying that the r value is the distance between the pivot and the point where the clay hits. However, the r value is not 0.5 meters here. The entire stick is 1.00 m, and the clay sticks at the point halfway from the pivot to the end. The pivot is in the middle.

Try adding your two equations for the force in the x directions together - this will eliminate the tension. Also, I for the Fx on the block m, the friction should be opposing the motion and be negative. One key word in the problem you may have missed: CONSTANT speed. So this means that the...

The equivalent resistance from the 10,5,20 is approximately 2.86 ohms, and for 90,90 is, as you said, 45 ohms. So you're saying that the order would then be [90=90]>20(top)>10(bottom)>[5>10>20]?

Homework Statement Rank the resistors according to to the rate at which energy is dissipated in them. Homework Equations P = I2R P = V2/R Iin=Iout at a node The Attempt at a Solution First I looked considered the 20 Ω (top) and the 10 Ω(bottom). The current in them would be the same, so...

I would suggest editing your question to give the entire problem in order to help people better help you... "what is the restoring force at the bottom" doesn't help me understand the problem very well. The restoring force is directed back towards the equilibrium position. Think about the...

That's the way I thought of it, but I'm just learning Le Chatlier's principle right now in my own class, so I'm far from an expert on this.

Not exactly sure with your second question involving the momentum not being conserved, but in regards to the first question: Mechanical energy is the sum of kinetic and potential energies. So think, what is the initial kinetic and potential energies compared to the final kinetic and potential...

The equilibrium reaction: Mg(OH)2(s) <==> Mg++ + 2 OH- According to Le Chatlier's principle for an exothermic reaction, if you lower the temp., the equilibrium reaction will shift right (the dissociation gives off heat and if there is less heat in the outer environment (lower temp.), then the...

The total stretched length when? Is there a force acting upon the spring? But to answer your question more directly, if you are correctly solving for x (which I cannot confirm without the problem info), then that is the change in x. Adding the initial x position and the change in x will give you...

Your post is vague; you should post the entire question to help people help you. Not exactly sure what you are trying to solve for here. From what you have, all I can say is that you should keep in mind that the x in Hooke's law is the change from the initial position of the spring to the final...

Why divide by 630? You have done the calculation for the torque from the plank. Again, the girl does not weigh 630 N.

The girl's weight is not 630 N. Recall the problem says: "don't neglect the weight of the plank when you do this problem".