Recent content by Matthewkind

Argh, I sincerely apologize! I is luminous intensity (obviously!), not luminous flux, which would be F.

Ah, I forgot to mention: E is the illuminance, I is the luminous flux, and s is the distance.

Homework Statement Two 640-candle lamps are placed 6.0 ft apart and 8.0 ft above a table. Calculate the illuminance on the table directly below one of the lamps. Homework Equations The illuminance equation, to the best of my knowledge is as follows: E = I/s^2 and E = (I/s^2)(cos x)...

The problem is three paragraphs with a bunch of blank spots. Starting from f(0) = 0 at constant velocity v, the distance function is f(t) = __[A]__. When f(t) = 55t the velocity is v = __[B]__. When f(t) = 55t + 1000 the velocity is still __[C]__ and the starting value is f(0) = __[D]__. In...

But you're right. I was being so close-minded at the time. I wonder why getting so worked up inhibits my ability to solve a problem logically. :/

Yes! Thank you so much! I believe I have solved the problem! I first expanded the problem so that (m, n-1) + (m, n) = (m+1, n) is m!/n!(m-n)! + m!/(n-1)!(m-n+1)! = (m+1)!/n!(m-n+1)!. Next I took the four terms of all denominators: n! (m-n)! (n-1)! and (m-n+1)! and multiplied them by each term...

Thanks for trying to help me. I learned a bit about the nature of the problem (which was never even touched upon in the book for some reason...).

I can't take it anymore. I'm losing my mind. I need to stop and come back to this later. I don't even have any more hair to pull.

How do you do that? (m,n-1) = m!/(n-1)!(m-n+1)!. (m,n) = m!/n!(m-n)!. m!/n!(m-n)! multiplied by n/(m-n+1)? Where does that part come in? I mean, if (m,n) + (m,n-1) = (m+1, n), then wouldn't (m+1, n) - (m,n) = (m,n-1)? I'm so completely confused!

I know that (m+1, n) = (m+1)!/n!((m+1)-n)!. But I can't get to this because I am still not sure what to do after I hit what was mentioned above...

(m, n) + (m, n-1) = (m+1, n). That's what I'm supposed to prove. So (m, n) = m!/n!(m-n!) and (m, n-1) = m!/(m-n+1)!(n-1)!. If I expand it, then I get: m(m-1)/n(n-1)(m-n)! + m(m-1)/(m-n+1)!(n-1)!. However, then I get stuck.

Oh, the commas confused me. The way it's written there were no commas. I see. Let me try re-starting the problem.

Oh, sorry. I meant it's alright if I take a break to cool my head. XD No, I won't leave any stones upright in this area!

I don't understand what you mean. Where are you getting (m, n-1) and (m+1, n)? ;__;

I'm already nineteen and I'm still struggling with this stuff! Is it even possible for me to grasp differential geometry and tensor analysis in my lifetime at this rate?!