oh, isn't that a "30, 60, 90" triangle if you draw an altitude from a vertex to the opposite side?? ok, maybe I'll try that...but...
what do I differentiate?? the two forumlas for area?
well, as stated the area of the square is just W^2...and although the formula for the area of triangle is (1/2)b(h), I don't know how to get to that...
to get the optimization part you need the equations for the area, differentiate them, and then find the min of f '(x), but I don't know...
HallsofIvy, I had the 3L + 4W = 10...As you stated, the sides of the triangle cannot be the same length as the square because you don't have to differentiate to find a minimum area...heres what i came up with for setting that equation equal to L...
L = (10-4W)/3...
so does this make sense...
I was wondering if someone could workout this problem...
The sum of the perimeters of an equilateral triangle and square is 10. Find the dimensions of the triangle and the square that produce a minimum total area.
Thanks for any help
yes I have and I came up with...
q(y^(q-1))(dy/dx) = p(x^(p-1))
but I'm stuck after I get here...i guess I could isolate dy/dx, but I'm not sure where to go from there...any help?
Ok guys, I'm new here and I need some help with a math problem...
The problem asks me to prove the power rule ---> d/dx[x^n] = nx^(n-1) for the case in which n is a ratioinal number...
the one stipulation is that I have to prove it using this method: write y=x^(p/q) in the form y^q = x^p...
Ok guys, I'm new here and I need some help with a math problem...
The problem asks me to prove the power rule ---> d/dx[x^n] = nx^(n-1) for the case in which n is a ratioinal number...
the one stipulation is that I have to prove it using this method: write y=x^(p/q) in the form y^q = x^p...