I guess my main problem was, to go into the specifics now, how it might be reasoned that a state with exotic properties like emergent gauge structure or topological order or fractionalisation of charge - as you point out - is equivalent to another standard definition of quantum SL (QSL) i.e. a...
Hi,
All articles on spin liquids I've seen treat them as insulators. This is understandable in the context in which they were first introduced i.e. the resonating valence bond state in which every electron is singlet-ed with every other, and thus essentially blocking conduction.
Given...
Yes, this is clear. My question was how does one see, mathematically or heuristically just with the BHH expression being given, that the hopping-terms prefer a state with a broken symmetry? For example, the ferromagnetic Heisenberg Hamiltonian has -S.S term which favours parallel alignment of...
Well, as I mentioned before and to be more explicit, I can argue phenomenologically that the U(1) is broken in the SF phase as follows: since U(1) symmetry is nothing but charge conservation (see for e.g. Fradkin's book "Field theories on Condensed matter") and since there is spontaneous...
Hi
With the Bose-Hubbard Hamiltonian (BHH) being invariant under a U(1)\equivO(2) symmetry transformation, it is said that the hopping-term in the BHH tends to break the U(1) symmetry as the system leaves the insulating phase. This is not clear to me.
However within the mean-field...
The answer comes from the AKLT hamiltonian, wherein at each site, the spin 1 is decomposed into 2 spin-1'2's. This is the ground state of the said hamiltonian and can be best understood within the Schwinger boson formalism.
Hello
I have come across this inexplicable fact mentioned in somewhere that for a chain of S = 1 spins, the adjacent bonds can all be in a singlet state i.e. singlets can be shared in this case (forming valence bond solids) but not, for example, for |S| = 1/2, the latter point being clear. I...
What cgk meant by the "totally symmetric representation" is actually the trivial representation. Landau & Lifgarbagez:Volume 3 explains in simple terms why this wonderful theorem is true (sort of like the Kraemers degeneracy theorem).
Mavi
Guessing another part of the answer: it seems that since the continuum limit or the lattice limit must yield the same critical exponents (due to scaling invariance after graining), the lattice structure itself must not matter for the exponents. I wonder if this reasoning is correct.
Mavi
I found out one part of the answer: changing the dimensionality of the lattice will change the critical exponents for the same model (say Ising). So the modified question would be whether the exponents change while changing the lattice structure (say square to triangle) for the same model in a...
Hi
When a particular model (say Ising) is solved on a particular lattice (say 2D triangular), do the critical exponents of the same model fall within the same universality class (have same critical exponents) as when solved on a different lattice (say 3D cubic)?
Thanks,
Mavi
So if there is a continuous band of energies connecting the ground and excited state of the d-wave superconductor (because it is gapless), why should the superconductivity be stable, since arbitrarily small thermal fluctuations can excite it? This should be true even if we consider large...
Right that makes sense; I guess its something similar to a p-n junction where the Fermi levels between the p and n sides develop a gap between each other.