It is. I just make stupid mistakes. Thanks! Do you see anything else wrong with the calculations? I think I calculated it with the right number I just typed it into here wrong.
Homework Statement
An alpha particle (a helium nucleus) is traveling along the positive x-axis at 1425 m/s when it enters a cylindrical tube of radius 0.700 m centered on the x-axis. Inside the tube is a uniform electric field of 5.00x10-4 N/C pointing in the negative y-direction. How far does...
Okay I think I still might be lost, but I'm thinking that the tension force on disk 2 will produce a torque that has the same direction as the angular acceleration, so even if it were negative they would both cancel out to give Tr=I(alpha). I don't really know where I am going with this, because...
I have no idea. I guess I'm not sure if the equations are the same because I don't know if they are both accelerating downwards. How do I know?
Also when I calculated the torque, did I use the right equation or should it have been negative?
Thanks for your help!
I would start with the idea that the -q(water)= q(ice)
This is because the water is warmer and it is losing heat to the ice. It will continue transferring heat until both are at the same temperature. Since the calorimeter has negligible heat capacity, it does not absorb any of the heat that the...
I think you probably have to do something with the impulse that the pad delivers to the egg:
The egg hits the pad with some initial velocity and then is brought to a complete stop before most likely bouncing up a little bit.
This is essentially an acceleration in the upward direction. Then...
The normal force is not equal to the force of gravity because there is another force acting in the vertical direction---the force being applied to the sled at the 30 degree angle.
Homework Statement
Two uniform disks with the same mass are connected by a light inextensible string supported by a massless pulley, on a frictionless axis. The string is attached to a point on the circumference of disk A. The string is wound around disk B so that the disk will rotate like a...
Thank you for your help so far by the way!
I set up an equation for the rotation, but I'm still a little confused on the rotation.
I(alpha)=F(friction)r
(1/2mr^2)a/R=F(frict)r
ma/2=F(frict)
F(frict)=
I guess I really don't know how to relate them?
I was also thinking that...
i would try setting up free body diagrams for all of the parts of the train. Then you can set up equations for the sum of the x and y force components for each train part and can combine them to solve for the 2 tensions.