Electric Field Problem in a Tube

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Homework Help Overview

The problem involves an alpha particle moving through a cylindrical tube with a uniform electric field. The objective is to determine the distance the particle travels before hitting the tube wall, given its initial velocity and the electric field strength.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations related to the force on the alpha particle due to the electric field and the resulting acceleration. There are questions about the accuracy of the calculations and potential mistakes in the process.

Discussion Status

Some participants are verifying their calculations and expressing uncertainty about specific values and units. There is an ongoing exploration of the calculations, with participants checking for errors and discussing the precision of their results.

Contextual Notes

Participants are working under the assumption that gravitational forces can be neglected, and they are focused on the effects of the electric field on the particle's motion. There is mention of potential typographical errors in the calculations presented.

mburt3
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Homework Statement


An alpha particle (a helium nucleus) is traveling along the positive x-axis at 1425 m/s when it enters a cylindrical tube of radius 0.700 m centered on the x-axis. Inside the tube is a uniform electric field of 5.00x10-4 N/C pointing in the negative y-direction. How far does the particle travel before hitting the tube wall? Neglect any gravitational forces. Note: mα = 6.64x10-27 kg; qα = 2e.


Homework Equations


Eq=F
d(delta)y=v(int)yt + 1/2at^2
d(delta)x=v(int)xt

The Attempt at a Solution



(5x10-4)(2)(1.6x10-19) = F = 1.6 x 10-22
F=ma
(1.6 x 10-22)/(6.67 x 10-27) = a = -2.41 x 10-4m/s^2

d(delta)y=v(int)yt + 1/2at^2
-.7= 0 + (.5)(-2.41 x 10-4)(t^2)
t= .007622s

d(delta)x=v(int)xt
d(x)= (1425)(.007622s)= 10.86 m

I'm not sure what I did wrong, but I checked my math twice so I guess it must be something with the process that I took. Please let me know if you can help! Thanks!
 
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(1.6 x 10-22)/(6.67 x 10-27) = a = -2.41 x 10-4m/s^2
Just wondering why it's not -2.41 x 104m/s^2
 
It is. I just make stupid mistakes. Thanks! Do you see anything else wrong with the calculations? I think I calculated it with the right number I just typed it into here wrong.
 
I didn't calculate it out. But now that I did it looks ok for the statement of the problem.

I got 10.85m carrying more precision, but that shouldn't be the problem.
 

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