but the right answer is left... "because the charged object will attract the pith ball, the force must be pointing to the right; that means the electric field points to the left"
is the book wrong?
In a pith-ball electroscope, a ball made of pith, which is a light-weight electrical insulator, is suspended from a hook via a silk thread. When the electroscope is placed in the vicinity of a negatively charged object on the right, the ball moves towards the object. What is the direction of...
Here's the answer:
"if friction is negligible, then the speed of the car after coming out of the circle is the same as the speed when it went in, because no work was done on it. The distance to travel toward the wall is 50m, which can be traversed in 1 second. but the car will have to...
I got that number my equalling 1/2mv^2 = 1/2kx^2 and solving for x...
I think the 50 meters the car travels doesn't include the above distance.
If you look at the answer in the back of the book, you'll understand what i mean.. one sec i'll get the link
It's a huge question, and I didn't want to confuse people...
but you're right... the car is maintaining a constant velocity of 50 m/s before and after the loop. And the distance from the end of the loop to the wall is 50 meters. So:
d = vt
t = d/v = 50/50 = 1 second.
To answer the...
that makes sense... but if angular frequency is the number of radians per second, then if we take one fourth of it.. that gives us the number of radians traveled in 1/4 of a second. i guess i don't understand become are final units will be Hz and not in seconds.
that makes sense - the time it takes to reach maximum displacement should be 1/4 of the period...
the equation for the period (in the book) is:
(2pi * (m/k)^0.5)1/4
the answer comes to 0.287 seconds
the answer they show is:
((k/m)^0.5)1.4 = 1.37 seconds
this question is so...
it doesn't really give that information... but the impulse idea actually makes sense.. but i get the wrong answer...
i don't know if this matters - but the way they showed the answer - it looks like it's 1/4th the angular frequency. the angular frequency is equal to square root (k/m). Do you...