Direction of electrostatic force and field?

AI Thread Summary
In a pith-ball electroscope, the ball moves towards a negatively charged object, indicating the direction of the electric field. The confusion arises from the relationship between the electric field and the force on the pith ball. The electric field points towards the negatively charged object, which is to the left, while the force on the ball, induced by the charge, is directed to the right. This suggests that the book may have presented the information incorrectly or ambiguously. Clarification on the interaction between induced charges and electric fields is necessary for accurate understanding.
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In a pith-ball electroscope, a ball made of pith, which is a light-weight electrical insulator, is suspended from a hook via a silk thread. When the electroscope is placed in the vicinity of a negatively charged object on the right, the ball moves towards the object. What is the direction of the electric field?

It should be to the right... because then the force on the negatively charged object would be pointing left... am i right?
 
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but the right answer is left... "because the charged object will attract the pith ball, the force must be pointing to the right; that means the electric field points to the left"

is the book wrong?
 
Puzzling, the negatively charged object would induce a small positive charge on the pith ball. As such, since the force on it is to the right, the field resulting the force must also point to the right (E field goes out from positive charges, and into negative ones).

Maybe the book phrased the layout of the system poorly? Or it could just be a mistake, unless we're both missing something.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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