Direction of electrostatic force and field?

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SUMMARY

The discussion centers on the direction of the electric field in relation to a pith-ball electroscope when exposed to a negatively charged object. Participants conclude that the electric field points to the left, as the negatively charged object attracts the pith ball, inducing a positive charge on it. This attraction results in a force directed to the right, confirming that the electric field direction is opposite to the force on a positive test charge. The confusion arises from the interpretation of the system's layout and the nature of electric fields.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with the concept of charge induction
  • Knowledge of the behavior of pith-ball electroscopes
  • Basic principles of force direction in electric fields
NEXT STEPS
  • Study the principles of electric field direction and force interactions
  • Explore charge induction effects in electrostatic systems
  • Review the operation and applications of pith-ball electroscopes
  • Investigate common misconceptions in electrostatics
USEFUL FOR

Students of physics, educators teaching electrostatics, and anyone interested in understanding electric fields and forces in electrostatic systems.

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In a pith-ball electroscope, a ball made of pith, which is a light-weight electrical insulator, is suspended from a hook via a silk thread. When the electroscope is placed in the vicinity of a negatively charged object on the right, the ball moves towards the object. What is the direction of the electric field?

It should be to the right... because then the force on the negatively charged object would be pointing left... am i right?
 
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but the right answer is left... "because the charged object will attract the pith ball, the force must be pointing to the right; that means the electric field points to the left"

is the book wrong?
 
Puzzling, the negatively charged object would induce a small positive charge on the pith ball. As such, since the force on it is to the right, the field resulting the force must also point to the right (E field goes out from positive charges, and into negative ones).

Maybe the book phrased the layout of the system poorly? Or it could just be a mistake, unless we're both missing something.
 

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