Recent content by mcKempt

NVM, found it. Had to plug the x-component of velocity into the first equation my instructor gave with the time we found. Thanks, this can be closed.

BTW - when I use the range equation for part B, I get 39.6 m.

I found it, had to split the initial velocity and use the horizontal component into my initial velocity when I did the quadratic. How am I suppose to know when to use the x or the y components when I solve a problem like this? Also, since I found time (rather simple, too) how do I solve part B?

Am I suppose to split the initial velocity into x and y components?

Ahhhh, I see now. I always thought the first equation was given by v_0 = {x_f - x_0}over{t}. So when I do it: I plug in my values into Δx = v_0 t + 1/2 a t^2, I get time to equal either 69.70 or -167.27 after using the quadratic equation. This is not right.

Homework Statement A rock is thrown off a 100 m cliff at an angle of 38 degrees below horizontal with an initial velocity of 20.0 m/s. a) What is the total time in flight? b) What is the horizontal range? c) What is the max height reached by the rock? Homework Equations x = x_0 +...