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Undergrad Acceleration as derivate of velocity
What i am saying is that there is a function that v(s(t)) [v is a function of s which is a function of t] So in that case, when chain rule is applied i get a= dv/ds * ds/t Am i right in my thinking ? -
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Undergrad Acceleration as derivate of velocity
yes i know the chain rule if y=f(g(x)) then dy/dx = df/dg * dg/dx but confused that how is that applied here? -
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Undergrad Acceleration as derivate of velocity
I have problem understanding the following derivation: a = dv/dt v= ds/dt (i get this part) but then, a = (dv/ds)(ds/dt) I can't understand the above equation? Please can you tell me how 'a' gets that value? -
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A point charge Q is located on axis.Find flux
The right question i should ask is that how to calculate the flux when it makes theta at center?- mentalguy
- Post #3
- Forum: Advanced Physics Homework Help
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A point charge Q is located on axis.Find flux
A point charge Q is located on the axis of a disk of radius R at a distance b from the plane of the disk Show that if one fourth of the electric flux from the charge passes through the disk, then R= √3 b I have looked it through all angles possible for me but it seems to evade me. Got...- mentalguy
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- Charge Flux Point Point charge
- Replies: 2
- Forum: Advanced Physics Homework Help