Recent content by MGCLO

  1. M

    Cannot understand Normal Force, Solution to problem

    Normal Force is equal to the force acting on the surface. which is in case Y-Component of G.and it must be perpendicular to the surface. so when we have an angle over here. you need to get the Y-component of the FG(Force of Gravity). which is equal to the normal force. if you don't have an...
  2. M

    Capillary action

    B. because on the outside. there is more fluid. therefore. more weight that is the fluid putting on the glass. but on the inside. less fluid and the same surface are touching the tube! so it would be easier for the fluid to rise inside the tube. this question is really common sense! i never did...
  3. M

    Tension on a pullstring walker

    when i do the geometry i get an unreasonable answer of cosθ= adjacent/hyp cos10= 50/ hyp hyp=50/ cos10 hyp = 49.24 N. is that correct? i did it wrong last time. i belive this is correct. answer is reasonable this time!
  4. M

    Tension on a pullstring walker

    here is how the problem looks. http://i39.tinypic.com/2d0j4wg.png a pullstring walker is in the middle of a string that is connected to two mountain sides. the string formes an angle of 10 degrees under the horizontal. the walker has a mass of 50 KG. find the tension of the string any...
  5. M

    Please an answer - 2 crates, a rope and friction

    yes. 21KG(10M/S^2) -FT= ma 210-FT=21(2.75) FT=152.25
  6. M

    Please an answer - 2 crates, a rope and friction

    how about the tension on the cord between A and B ft=152.25 ???
  7. M

    Setting Derivative = 0 and solving

    i thought they're supposed to show the work?
  8. M

    Please an answer - 2 crates, a rope and friction

    can anybody check my answer?
  9. M

    Cannot understand Normal Force, Solution to problem

    a guy already answered the question on yahoo answers!
  10. M

    Please an answer - 2 crates, a rope and friction

    ok I showed my work for that part. can anyone tell me if 367.5 is correct?
  11. M

    Please an answer - 2 crates, a rope and friction

    correct my bad got confused. using different weights in one problem does not make sense either. so 210-ft= 2.75(210) I got ft= 367.5 ?
  12. M

    Please an answer - 2 crates, a rope and friction

    well since we don't have an angle. then 210-ft= 2.75(5) so 210-ft= 13.75 -ft = 13.75-210 ft= 196.25 ? is that correct!
  13. M

    Please an answer - 2 crates, a rope and friction

    I figured out the acceleration part but I cant figure out the Tension!
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