Setting Derivative = 0 and solving

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Homework Help Overview

The original poster is working on a problem involving setting a derivative equal to zero to solve for a variable, specifically addressing the legality of manipulating the equation when the derivative is a fraction with the variable in both the numerator and denominator.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions whether it is valid to multiply zero by the denominator of a fraction when solving for the variable, raising concerns about the implications of having the variable in the denominator.

Discussion Status

Some participants suggest that the approach of multiplying both sides by the denominator is acceptable, while also providing an alternative method of dividing by a term. There is an ongoing exploration of the validity of these methods without reaching a consensus.

Contextual Notes

Participants note that showing work is typically a requirement for homework problems, although the original poster emphasizes that their question is more conceptual and uses a simplified example rather than the actual problem at hand.

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Homework Statement


I'm currently working on a problem that requires me to set the derivative = 0 and solve for a variable (call it x). The derivative comes out to be a fraction, with x terms in both the numerator and denominator. Is it legal to just multiply 0 by the denominator (thereby canceling it) even if it has the term of interest as part of it?

Simple Ex: say the derivative came out to be x-3 / 2x. And I want to solve for x.
When I set that derivative equal to zero, can i just multiply 0 by 2x, leaving x-3=0? So x=3

Homework Equations



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The Attempt at a Solution


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That should be ok. You could also divide the left side by x / x, assuming that x is not equal to zero, resulting in:

( 1 - (3/x) ) / 2 = 0
 
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thank you
 
rcgldr said:
That should be ok. You could also divide the left side by x / x, assuming that x is not equal to zero, resulting in:

( 1 - (3/x) ) / 2 = 0

i thought they're supposed to show the work?
 
MGCLO said:
i thought they're supposed to show the work?

It is a requirement for HW problems, but my question was geared towards a concept. The equation I'm deriving for the HW would probably take up an entire line on here. The example I put on was just that, an example, it wasn't even close to my actual problem (although I wish it was haha)
 
MGCLO said:
i thought they're supposed to show the work?
Multiplying both sides by 2x is just as valid as dividing the left side by x/x. I only showed that as an alternative in case there's a situation where that would be a better option for a different equation.
 

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