Recent content by MHrtz

I would imagine the effect of the gas compression would be negligible. Theoretically, air should behave like an ideal gas in this case because it is under high temperatures. If you want to verify, you could always determine the compressibility factor of air at the inlet condition and outlet...

So, essentially, you are need an electronic control system for compressed air. I'm assuming you were asking for a control sequence rather than for actual devices to control. I think you are on the right tack with the flow control device with the transducer. You will definitely need that. You...

Ok, so i did some more problems and came across this one: an = (1 + 2/n)n When I took the limit I though it was 1 but the book said that the limit was e2. How is this possible?

What about other sequences like an {1 n = 2k k is an integer {0 otherwise It's divergent only sometimes right?

I've been having some trouble understanding how to determine if a sequence is divergent or convergent. For example an = cos(2/n) I know if I take the limit as n ->\infty then I will get 1. So the sequence has a limit but does having a limit mean that the sequence is convergent.

I factored and then took the square root and came up with this: (y^3)/2 + 1/2y^3

Homework Statement Determine the arc length of the function on the given interval x = (y^4)/8 + 1/(4y^2) from 1 to 2 The arc length formula \int (f'(x)2 + 1).5 dx The Attempt at a Solution I used the arc length formula but don't know where to go from here. Usually these...

Ok. So I get 4/e now as my final answer. My mistake was that I dropped a negative while carrying out my evaluation. For the first integral I tried a different attempt but the answer is still off: u = ln(2x+1) du = 2/(2x+1) dx dv = dx v = x xln(2x+1) - \int 2x/(2x+1) dx u = 2x + 1 du = 2 dx x...

-2cosxecosx - 2\intsinxecosx dx u = cosx du = -sinx dx 2\inteudu -2cosxecosx + 2eu [-2cosxecosx + 2ecosx] evaulated from 0 to pi What about this?

I tried your method for the third integral but still got a wrong answer. I used a calculator and determined that the actual answer was e - (1/e). Here's what I did: s = cosx ds = -sinx dx \int2sinxcosxecosxdx = -2\intsesds u = s du = ds dv = esds v = es -2ses - \intesds...

If u = cosx then does this mean that dv = 2sinx ecosx dx?

I did get the integral on the right then I made u = 2x + 1, du = 2 dx, and (u - 1) = 2x

Homework Statement Take the integral of the following: 1. ln(2x+1) 2. arctan4x 3. ecosxsin2x evaluated from 0 to pi The Attempt at a Solution 1. took the derivative of ln(2x+1) and integrated dx. my solution was: xln(2x +1) + x + [(2x + 1)-2]/2 + C The books answer was...

ok I simplified both sides to where x = x. Thank You, I can take it from here.:cool:

I tried simplifying but then this happened.