Recent content by mikea2424

Thank you very much for replying to my original post. I know that there is a zero at x=1. I know this zero touches the x-axis meaning that it is an even multiplicity. So the top of the fraction should look like (x-1)^2. The vertical asymptotes are x= \pm3. So the bottom of the fraction looks...

Hello, I'm studying for a test this Friday and I have two problems that have completely stumped me. I'm not sure how to solve either. Any help would be greatly appreciated.