Recent content by mit

As you say 33% by weight and 1.25g/ml is ... gr/l do you see it now?

e is a Neperiaans logaritmic function so it looks strange to me that it was used. For me 0.001% was the correct answer. If you are not sure about ppm it is part per million

carbon are carbon atoms and if you know that 7.7x10^22 gr 100% is than you can calculate how mutch % 7.7x10^17 gr is. Why do you use e^-5?

A handbook of analytical chemistry can help you with the mathematical explanation. For your pH range you can use the NaH2PO4/Na2HPO4 system range pH 6 - 8 with the middle value H+=Kz2 or -logKz2 =7.22 Greetings

Buffersystems H3PO4/NaH2PO4 or NaH2PO4/Na2HPO4 or Na2HPO4/Na3PO4

Why do you use NaCl?

remember Kw is the ionproduct of water at a given temperature. So {H+}*{OH-}= 3.49e-13 next {H+}*{OH-} can be seen as {H+}e2 so what to do next to gain {H+} from Kw?

The crystal will grow bigger.

Google: FSHN101 Starch

40 gr in 1 liter gives 1 mol NaOH solution, I think the book is wrong because I can't see any reason for using 10 gr that is not given in the question.

1) write first the equation 2) 12 gr C contains 6.027*10^23 atoms how mutch is this for 20.5 g? 3) antacids is this formic acid?

with a electrolytic cell containing water and a little sulfuric acid (for a good conduction) a anode and kathode and dc current from an outside voltage source. At the negative side you will obtain H2 at the positive side O2.

H2Ind- (red) pH=6.3 HInd-- (blue) pH=11.5 Ind--- (yellow-orange) Mg2+ + HInd-- double arrow MgInd- + H+ wine-red colour before EP buffer pH 6.6-10.5 (NH4Cl/NH3) further titration with EDTA around EP MgInd- (wine-red) + HY--- double arrow MgY-- + HInd-- (blue). It is not easy to see the...

Your equation is good, take a look at the left side of it, you will see that 1 atom Mg take 2 molecules HCl with a release of 2 H forming quickly H2 so 2/8 of the genesis from H2 is the responsibilty from the Mg. In the calculation you get 0.066575 mol H2 so than divide this amount by 2...