Chemistry - acids, bases, equilibrium

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SUMMARY

The equilibrium constant for water, Kw, is 3.49e-13 at a specific temperature, indicating the concentration of hydrogen ions, [H+], in a neutral aqueous solution. By applying the equation Kw = [H+][OH-], it is determined that [H+] equals 3.49e-6. Consequently, the pH of the solution is calculated to be 5.457, confirming that Kw varies with temperature and affects the pH of neutral solutions.

PREREQUISITES
  • Understanding of equilibrium constants in chemistry
  • Knowledge of the relationship between pH and hydrogen ion concentration
  • Familiarity with logarithmic functions
  • Basic concepts of acid-base chemistry
NEXT STEPS
  • Study the effects of temperature on Kw and pH
  • Learn about the ion product of water at different temperatures
  • Explore advanced acid-base equilibrium calculations
  • Investigate the role of pH in chemical reactions
USEFUL FOR

Chemistry students, educators, and anyone interested in understanding acid-base equilibria and the impact of temperature on pH levels.

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Homework Statement


Like all equilibrium constants, Kw varies somewhat with temperature. Given that Kw is 3.49e-13 at some temperature, compute the pH of a neutral aqueous solution at that temperature.

Homework Equations


Kw = [H+][OH-]
pH = -log[H+]

The Attempt at a Solution


3.49e-13 = [H+]*10e-7
[H+] = 3.49e-6
pH = 5.457
 
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remember Kw is the ionproduct of water at a given temperature. So {H+}*{OH-}= 3.49e-13 next {H+}*{OH-} can be seen as {H+}e2 so what to do next to gain {H+} from Kw?
 

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