Recent content by mithilsheth

Vyi= sqrt of vyf^2 + 2g divided by y?

would i have to isolate the formula?

so would the equation be Vyf^2 = Vyi^2 + 2g(delta y)

velocity along the y axis

the velocity ?

how far (delta y) the water balloon would go?

the water balloon should just graze the ceiling which is 3.3 meters tall and is going at a initial velocity at 9.7 m/s

I don't know

i need to find the angle. i really do not know which equation to use...

Homework Statement Some enterprising physics students working on a catapult decide to have a water balloon fight in the school hallway. The ceiling is of height 3.3 m, and the balloons are launched at a velocity of 9.7 m/s. The acceleration of gravity is 9.8 m/s2 .At what angle must they...

delta x = 1/2 (1.51)(5.6394)^2 delta x = 24.0111384 that is what i got this time...

i also did substitute 5.6394 s for the time rather than 7.8 seconds, and i got 66.4208532002 for delta x. but this was wrong. what did i do wrong?

Homework Statement A subway train starting from rest leaves a station with a constant acceleration. At the end of 7.8 s, it is moving at 11.778 m/s. What is the train’s displacement in the first 5.6394 s of motion? Answer in units of m Homework Equations a= velocity final - velocity...

ok, i have one more question i need help with...

so the initial vertical speed would be 11.8793939239 m/s ?