yeah the original integral was \int[0,4]Y^{3/2}(16-Y^{2})^{1/2} dy
which i simplified to
64\int(0,1) t^{(5/4)-1}(1-t)^{(3/2)-1} dt
using Gamma(x)=int(0,oo)tx-1e-tdt, =>> \beta(5/4, 3/2)hence i am trying to solve \beta(5/4, 3/2)
= \Gamma(5/4)\Gamma(3/2) / \Gamma((5/2)+(3/2))
i am trying to...