Recent content by mkematt96

  1. mkematt96

    Linear Abrasion Testing PVC/Polymer Blend Hoses

    Working on a research project to develop a test standard for abrasion testing pressure washer hoses. Ideally this could be used on any sort of hose. We have a set procedure that has worked on a couple hoses that looks like this: .Weight applied is constant .Cycle speed is constant .Constant...
  2. mkematt96

    Force required to dislodge a sphere from pipe (Valve design)

    I'm designing a valve that uses a ball to seal the valve. When the valve is empty there is no force acting on top of the ball. When water flows in, it will push up on the ball to dislodge it, water will flow into the valve and push the ball up until it seats into the top hole/chamfer which then...
  3. mkematt96

    Energy dissipated in a resistor during a time interval?

    So then if the voltage is changing I could integrate with respect to time: Vs = ∫ 400t^2 dt from 0 to .4 s which is equal to 8.533 V then divide by 100 ohms to find the current .08533 amps. Then integrate power with respect to time: Wr= ∫ ( .08533^2 * 100) dt from 0 to .4 sec ?
  4. mkematt96

    Energy dissipated in a resistor during a time interval?

    Homework Statement Homework Equations P = I*V energy dissipated = wr = ∫ ( P *dt) ... t is from 0 to .4 seconds vs = 400t^2 = 400 * (.4^2) = 64 V The Attempt at a Solution Using KVL I said Vs ( 64 V) = 100 * i ... I found that I was 64/100 = .64 amps. I then said power is .64 amps ^ 2 *...
  5. mkematt96

    Engineering Help finding error in my Circuit Analysis

    After making these changes I got my numbers to match the LT Spice number! Thanks!
  6. mkematt96

    Engineering Help finding error in my Circuit Analysis

    Homework Statement Homework EquationsThe Attempt at a Solution My values for i1,i2,and i3 were: -.005179,-.002857 and .004857. When I ran the same circuit through LT Spice the values they gave me were .00059081,.000809628, and .00119037. Where did I make my error? * as a side not I...
  7. mkematt96

    Solve Using Method of Node Voltages

    Okay that makes sense thanks. One more quick question... Is the voltage across that 5 ohm resistor also -3.214 V or would it be positive 3.214 V ?
  8. mkematt96

    Solve Using Method of Node Voltages

    So I re did the problem taking the (v2-v1)/1 ohm out of the problem and got the right answer. My question is, why don't we need to account for this?
  9. mkematt96

    Solve Using Method of Node Voltages

    That is a voltage source.
  10. mkematt96

    Solve Using Method of Node Voltages

    Homework Statement [/B] Homework Equations This problem was from a practice exam. I know what V1 and V2 should be but can't get my answer to match. V1 should be -3.214 V and V2 should be -12.214 V The Attempt at a Solution See attached picture for my work. [/B]
  11. mkematt96

    Dynamic Shear Force on a Brake Pad

    I'm looking for a way to calculate the shear force applied to a brake pad from stopping ( a small engine brake pad stopping a fly wheel). I know shear stress is shear stress/ area , would this apply for a dynamic application as well? Would I need to calculate the force to stop the flywheel at a...
  12. mkematt96

    Complex Numbers and Euler's Identity

    I agree but the professor wants us to solve it using Euler's identities
  13. mkematt96

    Complex Numbers and Euler's Identity

    Theta should be the inv(tan(-3/4))= -.6435+pi =2.498 which fixes the sign error when I plug that in. The thing I am confused on is, is exp(ln(5))* [ cos(2.498)+isin(2.498) ] is that Z ? because that expression is equal to -4 +3i, but exp(-4+3i) ISNT equal to -4+3i
  14. mkematt96

    Complex Numbers and Euler's Identity

    Homework Statement exp(z)=-4+3i, find z in x+iy form Homework Equations See attached image. The Attempt at a Solution See attached image. exp(z)=exp(x+iy)=exp(x)*exp(iy)=exp(x)*[cos(y)+isin(y)] ... y=inv(tan(-3/4)=-.6432 ... mag(-4+3i)=5, x= ln (5)..exp(ln(5))=5 ...
  15. mkematt96

    Finding Magnitude of complex number expression

    Homework Statement We are given Z, and are asked to find the magnitude of the expression. See attached picture(s) Homework Equations See attached pictures(s) The Attempt at a Solution When I solved it on the exam, I did it the long way using De Moivre's theorem. I ended up making a few sign...
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