i could reconsider however it's something I'm being asked for. :(.
yep i know the answer must be E=Q/(4pi*r^2)ε.
and i know also the charge on the sphere it's all over the "surface area" and that the distance from the center to the point would be R+0.00000100 m.
Once i got the Electric...
So the problem statement is:
A conducting solid sphere (R = 0.167 m, q = 6.63·10–6 C) is shown in the figure. Using Gauss’s Law and two different Gaussian surfaces, determine the electric field (magnitude and direction) at point A, which is 0.00000100 m outside the conducting sphere. (Hint: One...
Well the professor asked us for bring both methods in terms of y as function of theta & theta as function of y;
I already did in terms of dy. making the substitution of cosine(θ) = x/√x^2+y^2 and then integrating.
but now i need the other method. y in terms of "θ"
Well the main problem here its once a i get the integral i do not how to put dy as function of thetha and then integrate ; at the end that's what i get
Ex=integral (dE*cos\theta)=(\lambda/4\pi\epsilon)
times the integral of cos(\theta)dy/x^2+y^2
where i can easily find the cosine and...
yeah actually i make the change of variables & i end up.. with "uv" terms.
then i found the angle to make them 0. because it was the cross product terms then i just got a u^2 and v^2 with sin & cos =6 at this point i didn't know how to reorder the equation.
that's why i go back to the...
Because what i tried to do its to re-write the equation " x^2+xy+y^2=6" which i found easier. then i plugged into it the "x" and "y" the problems gives.
but what i am not really sure if it means "elipse standard form"; i think the angle i got it's right since "...
Hi; I've been trying to solve the problem myself but i really don't what could be wrong;
The problem says :
Make the change of variables
x=ucos−vsin
y=usin+vcos
where the angle 0<(phi)<2 is chosen in order to eliminate the cross product term in
x^2+xy+y^2=6
Then find the standard form of...