Recent content by monkeykoder

I'm pretty sure if I were allowed to use it in cases of magnetization there wouldn't be a section "6.3.1 Ampere's Law in Magnetized Materials"

If I'm not mistaken there is some reason not to use that statement of ampere's law in cases of magnetization.

Ampere's law for polarized objects is about 3 sections ahead of where the problem is located in the book (not that that would usually stop me...).

Don't have Ampere's law to work with and not allowed to use cylindrical coordinates for some reason.

Homework Statement A long cylinder of radius R carries a magnetization \vec{M}=Ks^{2}\hat{\phi} where k is a constant, s is the distance from the axis, and \hat{\phi} is the usual azimuthal unit vector. Find the magnetic field due to \vec{M} for points inside and outside the cylinder.Homework...

That's why I'm having trouble asking a question in such a way as to not have the test question answered for me but to get a better grasp on the conceptual idea. I have the idea figured out now I'm pretty sure so I'll get on with it now. I'm sorry for posting this in the homework help section...

Problem I'm having is I'm trying to ask a question that helps me with a test problem I have without getting help on the test problem itself.

Polarized sphere radius a conducting shell radius b. How will the added charge Q distribute over the shell. Just looking for a conceptual jump to solve. Specifically a non-neutral conductor charged to a value Q is submitted to an electric field how do I calculate how the additional charge is...

b is the radius of the outer sphere Q_b is the bound charge on the inner polarized sphere.

I've calculated the charge distribution due to the polarized sphere I can't figure out how to work in the charge that has been placed on the conducting shell. So assuming no charge on the conducting sphere \sigma = \frac{3Q_{b}cos(\theta)}_{\pi b^{3}} I can't find a way to include the added...

My reasoning (probably flawed) is that the field due to the polarized sphere is taken care of through polarization of the conductor then the added charge should be free of the field.

Homework Statement Have a permanently (uniformly not radially) polarized sphere surrounded by a charged conductor How is the charge on the conductor distributed (the added charge)? Homework Equations The Attempt at a Solution Since the conductor cancels the field generated by...

I can't wait till you see L' Hospital's rule it is a real mind bender when you first see it. P.S. AP Calculus isn't necessarily equivalent to college calculus I have known many people who couldn't get into college calculus who had passed AP calculus with a 5 on the AP test.