# Recent content by mparsons06

V2 = V1*(T2 / T1)*(P1 / P2) V2 = (8.18 cm^3)*(289 K / 289 K)*(212 kPa / 101 kPa) V2 = (8.18 cm^3)*(2.099 kPa) V2 = 17.17 cm^3 Correct?

T2 / t1 = 289 k / 289 k = 1 k?

The temperature is a CONSTANT 16.0ºC...

Pressure at the surface is 1 atm = 101 kPa. Pressure at 11 m = 2.09 atm = 212 kPa. V2 = V1*(T2 / T1)*(P1 / P2) V2 = (8.18 cm3)*(289 K)*(212 kPa / 101 kPa) V2 = 4962 cm3 That can't be right... What do I need to have everything converted to? Do I convert them to the following: T1 = 16.0ºC +...

Homework Statement A scuba diver releases a 2.50-cm-diameter (spherical) bubble of air from a depth of 11 m in a lake. Assume the temperature is constant at 16.0ºC, and the air behaves as a perfect gas. How large is the bubble when it reaches the surface? Homework Equations V2 = V1*(T2...

So I got 0.0182 with my calculator in radians... Is that correct?

I changed my calculator to radians: x(t) = A sin (sqrt (k/m) * t) x(t) = (0.290) sin(sqrt (2.41 / 1.450) * 0.490T) x(t) = 0.145 m

So I did: x(t) = A sin (sqrt (k/m) * t) x(t) = (0.290) sin(sqrt (2.41 / 1.450) * 0.490T) x(t) = (0.290) sin(1.29 * 0.490T) x(t) = (0.290) sin(0.6321T) x(t) = (0.290)(0.011) x(t) = -0.00319 m Does that seem correct to you?

Can you help me with part b?

Homework Statement A 1.450 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.700 N to displace the glider to a new equilibrium position, x= 0.290 m. a.) Find the effective spring constant of the system. b.) The glider is...

I figured it out. Thanks.
12. ### Simple Pendulum - Maximum Speed

I drew the diagram, but I'm not sure how to find the potential energy?
13. ### Simple Pendulum - Maximum Speed

1. Homework Statement : A simple pendulum has a mass of 0.25 kg and a length of 1.0 m. It is displaced through an angle of 5.0° and then released. 1. What is the maximum speed? 2. What is the maximum angular acceleration? Answer: 0.855 rad/s2 3. What is the maximum restoring force? Answer...