Recent content by mparsons06
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How Large Will the Air Bubble Be When It Reaches the Surface?
V2 = V1*(T2 / T1)*(P1 / P2) V2 = (8.18 cm^3)*(289 K / 289 K)*(212 kPa / 101 kPa) V2 = (8.18 cm^3)*(2.099 kPa) V2 = 17.17 cm^3 Correct?- mparsons06
- Post #9
- Forum: Introductory Physics Homework Help
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How Large Will the Air Bubble Be When It Reaches the Surface?
T2 / t1 = 289 k / 289 k = 1 k?- mparsons06
- Post #7
- Forum: Introductory Physics Homework Help
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How Large Will the Air Bubble Be When It Reaches the Surface?
The temperature is a CONSTANT 16.0ºC...- mparsons06
- Post #5
- Forum: Introductory Physics Homework Help
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How Large Will the Air Bubble Be When It Reaches the Surface?
Pressure at the surface is 1 atm = 101 kPa. Pressure at 11 m = 2.09 atm = 212 kPa. V2 = V1*(T2 / T1)*(P1 / P2) V2 = (8.18 cm3)*(289 K)*(212 kPa / 101 kPa) V2 = 4962 cm3 That can't be right... What do I need to have everything converted to? Do I convert them to the following: T1 = 16.0ºC +...- mparsons06
- Post #3
- Forum: Introductory Physics Homework Help
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How Large Will the Air Bubble Be When It Reaches the Surface?
Homework Statement A scuba diver releases a 2.50-cm-diameter (spherical) bubble of air from a depth of 11 m in a lake. Assume the temperature is constant at 16.0ºC, and the air behaves as a perfect gas. How large is the bubble when it reaches the surface? Homework Equations V2 = V1*(T2...- mparsons06
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- Air Bubbles Gases
- Replies: 9
- Forum: Introductory Physics Homework Help
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Spring Constant and Oscillations -
So I got 0.0182 with my calculator in radians... Is that correct?- mparsons06
- Post #11
- Forum: Introductory Physics Homework Help
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Spring Constant and Oscillations -
I changed my calculator to radians: x(t) = A sin (sqrt (k/m) * t) x(t) = (0.290) sin(sqrt (2.41 / 1.450) * 0.490T) x(t) = 0.145 m- mparsons06
- Post #8
- Forum: Introductory Physics Homework Help
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Spring Constant and Oscillations -
So I did: x(t) = A sin (sqrt (k/m) * t) x(t) = (0.290) sin(sqrt (2.41 / 1.450) * 0.490T) x(t) = (0.290) sin(1.29 * 0.490T) x(t) = (0.290) sin(0.6321T) x(t) = (0.290)(0.011) x(t) = -0.00319 m Does that seem correct to you?- mparsons06
- Post #5
- Forum: Introductory Physics Homework Help
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Spring Constant and Oscillations -
Can you help me with part b?- mparsons06
- Post #3
- Forum: Introductory Physics Homework Help
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Spring Constant and Oscillations -
Homework Statement A 1.450 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.700 N to displace the glider to a new equilibrium position, x= 0.290 m. a.) Find the effective spring constant of the system. b.) The glider is...- mparsons06
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- Constant Oscillations Spring Spring constant
- Replies: 11
- Forum: Introductory Physics Homework Help
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Height of Blood Transfusion - ?
I figured it out. Thanks.- mparsons06
- Post #4
- Forum: Introductory Physics Homework Help
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Simple Pendulum - Maximum Speed
I drew the diagram, but I'm not sure how to find the potential energy?- mparsons06
- Post #3
- Forum: Introductory Physics Homework Help
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Simple Pendulum - Maximum Speed
1. Homework Statement : A simple pendulum has a mass of 0.25 kg and a length of 1.0 m. It is displaced through an angle of 5.0° and then released. 1. What is the maximum speed? 2. What is the maximum angular acceleration? Answer: 0.855 rad/s2 3. What is the maximum restoring force? Answer...- mparsons06
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- Maximum Pendulum Simple pendulum Speed
- Replies: 3
- Forum: Introductory Physics Homework Help
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Height of Blood Transfusion - ?
Okay. So to find pressure difference: P = 8 * η * L * Q / pi * r4 P = 8 * (0.004 Pa*s) * (0.0407 m) * (6.5 x 10-8 m3/s) / pi * (0.000194 m)4 P = 19023 Pa If that is correct, how do I find height from this?- mparsons06
- Post #3
- Forum: Introductory Physics Homework Help
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Flow Rate Problem: Solve for Time to Pour 6L SAE 10 Oil
Could you please check out my question on Height of Blood Transfusion? Thanks.- mparsons06
- Post #15
- Forum: Introductory Physics Homework Help