Height of Blood Transfusion - ?

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SUMMARY

The discussion centers on calculating the height at which a blood transfusion bottle must be placed to achieve a required flow rate of 3.90 cm³ per minute through a needle with a diameter of 0.388 mm. Using Poiseuille's law, the pressure difference was calculated to be 19023 Pa. The density of blood was established at 1.05 x 10³ kg/m³, and the viscosity was noted as 4.0 x 10⁻³ Pa·s. The final solution for the height was successfully determined by the user after initial calculations.

PREREQUISITES
  • Understanding of fluid dynamics, specifically Poiseuille's law
  • Knowledge of unit conversions for fluid measurements
  • Familiarity with the properties of blood, including density and viscosity
  • Basic physics concepts related to pressure and height in fluid systems
NEXT STEPS
  • Study Poiseuille's law in detail to understand its applications in fluid flow
  • Learn about the effects of viscosity on flow rates in different fluids
  • Explore the principles of hydrostatics to relate pressure and height in fluid systems
  • Investigate the physiological implications of blood flow rates in medical settings
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Medical students, healthcare professionals, and anyone involved in fluid dynamics or transfusion medicine will benefit from this discussion.

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Homework Statement



A patient is to be given a blood transfusion. The blood is to flow through a tube from a raised bottle to a needle inserted in the vein. The inside diameter of the 4.07 cm long needle is 0.388 mm and the required flow rate is 3.90 cm3 of blood per minute. How high should the bottle be placed above the needle? Obtain ρ and η from the Tables in the book. Assume the blood pressure is 18.5 torr above atmospheric pressure.

Homework Equations



ρ of blood: 1.05 x 103 kg/m3
η of blood: 4.0 x 10-3 Pa*s

I converted all the numbers to the necessary units:

Inside diameter = 0.388 mm = 0.000388 m
Length of needle = 4.07 cm = 0.0407 m
Flow rate = 3.90 cm3/min = 6.5 x 10-8 m3/s
Blood pressure = 18.5 torr above atmospheric pressure = 2466 Pa + 101300 = 103766 PaCan someone please help me out on where to start?
 
Last edited:
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Looks like you would use Poiseuille's law, as in your other recent thread.
 
Okay. So to find pressure difference:

P = 8 * η * L * Q / pi * r4
P = 8 * (0.004 Pa*s) * (0.0407 m) * (6.5 x 10-8 m3/s) / pi * (0.000194 m)4
P = 19023 Pa

If that is correct, how do I find height from this?
 
I figured it out. Thanks.
 

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