Recent content by MrNonexistent

x = \frac{\sqrt{-k}}{A} \pm AH is that right? i am so braindead.

im getting that A(x-h)^2 = \sqrt{-k} gives you one and if you subtract -K from this answer, you get the other x axis.

ooo... hm let's check it out.

Homework Statement 1) find the vertex, 2) find the x intercepts in terms of a, h, and k, 3) explain how values of a, h, and k affect the graph Homework Equations y = A(x - h)^2 + k The Attempt at a Solution 1) (H,K) 2) aaaahhh i don't know... i just forgot. 3) A determines how...

so 4 \pm \sqrt{2*3} ?

by that, you just mean plugging it into a calculator and finding the answer, correct? which happens to be 6.5505 & 1.4495 correct?

ok i think i got it, is it just (x - [8+\sqrt{24}/2]) * (x - [8-\sqrt{24}/2])?

also those were wrong, i did it wrong. hold on

when i type in on Google quadratic formula, then i plug the equations in, it tells me x=16 and x = 8 ? not the answer i need.

Oh ok thanks. yea, i was just running factors over and over in my head and i wasn't coming up with anything, I'm kind of brain dead, so i wasn't sure if it was just me. Thanks.

I forgot How to do these... Homework Statement y = x^2 - 8x + 10 change into y = (x[plus or minus]A)*(x[plus or minus]B) I just forgot how to do these... real fast could someone solve w/ showing work? Thanks. I just don't remember how to do it...