Recent content by muhammed_oli

thanks, worked through and got it

Homework Statement Mercury is poured into a U-tube as shown in Figure a. The left arm of the tube has cross-sectional area A1 of 9.4 cm2, and the right arm has a cross-sectional area A2 of 4.50 cm2. One hundred grams of water are then poured into the right arm as shown in Figure b. (b) Given...

awesome, thank you

hm -dU/dx = Force(x) ?

Homework Statement The potential energy function for a system of particles is given by U(x) = −4x^3 + 3x^2 + 8x, where x is the position of one particle in the system. (a) Determine the force Fx on the particle as a function of x. Homework Equations du/dx[U(x)] = Fx The Attempt at a Solution...

thank you beary much! I got it right, 3 sig digits

k, going to solve for t(ramp) using kinematic first. v(f) = v(o)+at v(o) = 0 2.42 = 7.51t t = 0.3222 same, find t for the fall y = v(o)t-1/2(g)(t^2) -2 = -1.85t-4.9t^2 4.9t^2+1.85t-2 = 0 t = 0.4774 t(tot) = 0.3222+0.4774 = 0.7996 sec how does that look?

part c v=d/t is for constant velocity? this is what I am thinking, after I've found t from the other equation x=v(o)t+(1/2)at^2 a=0 x=v(o)(m/s)t(s) x=x(m)part d I used 7.51sin50 to get that answer. I'm not sure how to approach this.

Hm alright, so the range equation I used was for symmetric projectile motion. I get what you are saying, I seem to mess up once I start using anything beyond the basics. Okay for C I found the components for final ramp velocity to be 1.56i - 1.85j v=d/t Vf=d/t find t y=V(o)t-g/2(t^2) for t? I...

Homework Statement A block of mass m = 2.00 kg is released from rest at h = 0.300 m above the surface of a table, at the top of a θ = 50.0° incline as shown in the figure below. The frictionless incline is fixed on a table of height H = 2.00 m. a. Find a on the incline a=7.51 :) b. Find V(f)...