Recent content by murdrobe

A = xr2 / G so then i need to convert the units for G to bequerels? but what is R in the R-cm2/hr-mCi does that mean its 3.3 x 1002 is equal to the value in milicuries? 1002 due to my calculation being at 1m

this is FAR easier, thank you

We weren't given anything for this calculation, as a group we found an online calculator that said this was the formula for it. Although it'd be fantastic if there is a simpler way, I'm not sure how to do what you suggested either

Homework Statement 6. If the exposure rate from 137Cs at one metre is 2.50 mGy/h, how many bequerels are present? Homework Equations X=5.263 x 10-6 A∑(yiEi(μen/ρ)i)/r2 The Attempt at a Solution what I am looking to do isn't to solve the question, i need to rearrange the formula...

*shameless bump* this 1 has stumped me a little sorry.

Homework Statement 6. If the exposure rate from 137Cs at one metre is 2.50 mGy/h, how many bequerels are present? Homework Equations Exposure is a quantity that expresses the radiation delivered to a point at a certain distance. I1d12 = I2d22 I1 = the radiation intensity at...

yeah i was thinking about using the ideal gas laws as we are learning that in physics class at the moment. the issue is that we don't have a temp. not having that value will affect everything else and if i give the results just assuming STP i don't think it would be worthwhile including it in my...

sorry the reason why i didn't use the template is because i am writing up an experiment report and this was part of my evaluation, there wasn't a direct question asked of me. i am trying to find out the volume of air that i would need to be able to completely react 0.26 grams of magnesium...

i went that the amount of magnesium i have to react fits into a single mole (24.31 grams) 93.5 times. so i need the amount of oxygen that fits into a single mole 93.5 times. so 16:00 is a single mole of oxygen. 16/93.5 gives me the amount of oxygen that i needed. the oxygen is 21% of the...

i have done the maths based on an online conversion calculator that said 1 liter of air is equal to 0.001m^3 in volume. my chemistry teacher tells me that my maths is wrong but won't tell me how... here is what i wrote: Failing the above, a larger crucible would hold more oxygen and the...

thanks for that, the book was talking about a person so I am fine with using that as the quote. the thing I am stuck on is that I am not sure how water pressure works exactly. would it be: 4KPa over the whole area of his chest or 4KPa times the area of his chest or have i worked out that it...

sorry I am not quite sure what your asking.

the guys chest is 30cm by 30cm, I am using m as units hence the 0.3. we were taught that water pressure affects an area all at once but I am not sure how that works, would the 4.9Pa be for 1m^3 and i need to divide it by the 0.3^2 or am i right in saying it would be 4.9 equally spread across the...

hmmm i think i found a better way. the college library had a physics book stating that the maximum a pair of lungs would inflate at is 20KPa and that at 2m of depth the pressure starts becomming too much. so if i take that and then work it back. if i end up with more than 20KPa i can say that...

i don't think i squared the 11.81, if i do that gives me 0.71 PSI which is a more realistic answer. this would also show that the person can breathe through the reed.